Q:

Solve for p. 2(p+ 5) = 16 Solve for t. -3(t + 1) = 18Solve for x -2/5 (x+10)=-10 Solve for x. 2/3 (x -10)=-2

Accepted Solution

A:
Answer: 1) [tex]p=3[/tex] 2)[tex]t=-7[/tex] 3)[tex]x=15[/tex] 4) [tex]x=7[/tex] Step-by-step explanation: 1) Apply distributive property: [tex]2(p+ 5) = 16\\2p+10=16[/tex] Subtract 10 from both sides of the equation and then divide both sides by 2: [tex]2p+10-10=16-10\\\frac{2p}{2}=\frac{6}{2}\\p=3[/tex] 2) Apply distributive property: [tex]-3(t + 1) = 18\\-3t -3= 18[/tex] Add 3 to both sides of the equation and then divide both sides by -3: [tex]-3t -3+3= 18+3\\\frac{-3t}{-3}=\frac{21}{-3}\\t=-7[/tex]  3) Apply distributive property: [tex]-\frac{2}{5}(x+10)=-10\\\\-\frac{2}{5}x-4=-10[/tex] Add 4 to both sides of the equation: [tex]-\frac{2}{5}x-4+4=-10+4\\\\-\frac{2}{5}x=-6[/tex] Multiply both sides by [tex]-\frac{5}{2}[/tex]: [tex](-\frac{2}{5}x)(-\frac{5}{2}) =-6(-\frac{5}{2})\\\\x=15[/tex] 4) Apply distributive property: [tex]\frac{2}{3}(x-10)=-2\\\\\frac{2}{3}x-\frac{20}{3}=-2[/tex]  Add [tex]\frac{20}{3}[/tex] to both sides of the equation: [tex]\frac{2}{3}x-\frac{20}{3}+\frac{20}{3}=-2+\frac{20}{3}\\\\\frac{2}{3}x=\frac{14}{3}[/tex] Multiply both sides by [tex]\frac{3}{2}[/tex]: [tex](\frac{2}{3}x)(\frac{3}{2})=(\frac{14}{3})(\frac{3}{2})\\\\x=7[/tex]